Respuesta :
Answer:
[tex]\frac{6}{49}[/tex]
Step-by-step explanation:
GIVEN: There are two boxes. in the first box there are [tex]7[/tex] cards numbered from [tex]1[/tex] to [tex]7[/tex] the second box also contains [tex]7[/tex] cards from [tex]1-7[/tex] pick one card from each box.
TO FIND: probability that the sum of the two two cards is at least [tex]12[/tex].
SOLUTION:
sample case such that sum of cards is [tex]12[/tex] : [tex](5,7),(7,5),(6,6)[/tex]
sample case such that sum of cards is [tex]13[/tex] : [tex](7,6),(6,7)[/tex]
sample case such that sum of cards is [tex]14[/tex] : [tex](7,7)[/tex]
Total sample case such that sum is atleast [tex]12[/tex] [tex]=6[/tex]
Total sample cases[tex]=49[/tex]
probability that the sum of the two two cards is at least [tex]12[/tex][tex]=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}[/tex]
[tex]=\frac{6}{49}[/tex]
probability that the sum of the two two cards is at least [tex]12[/tex] is [tex]\frac{6}{49}[/tex]
