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Suppose you're playing hide and seek in a big house with 4 rooms upstairs and 5 rooms downstairs. You've looked in 2 of the downstairs rooms and know the hider is not those rooms. What is the probability the hider is downstairs given this information? (Assume equally likely outcomes).

Respuesta :

faithmary2001

Answer:

3/7

Step-by-step explanation:

1. there were a total of 9 rooms but you minus two due to the fact the hider isnt there and so you are left with 7

2. You also minus two from five and that gives you three

3. they ask for only downstairs so it would be 3/7