Answer:
8400 N
Explanation:
We are given that
Mass,m=1.2 kg
Initial speed,u=-8 m/s
Final speed,v=6 m/s
Time,[tex]\Delta t=2 ms=2\times 10^{-3} s[/tex]
[tex]1 ms=10^{-3} s[/tex]
We have to find the magnitude of the average force on the ball during this collision.
Change in momentum,=[tex]\Delta p=m(v-u)=1.2(6+8)=16.8 kgm/s[/tex]
Average force,[tex]F_{avg}=\frac{\Delta p}{\Delta t}[/tex]
Using the formula
[tex]F_{avg}=\frac{16.8}{2\times 10^{-3}}=8400 N[/tex]
Hence, the magnitude of the average force on the ball during this collision=8400 N
