The next day, the same cylinder of gas has a pressure of 4.690 atm, and its temperature is 8 °C. The temperature on the previous day is 19.85 °C.
What is temperature?
Temperature is the measurement of the hotness or coldness of a body.
By the Gay-Lussac equation
[tex]\dfrac{P_1}{T_1} =\dfrac{P_2}{T_2}[/tex]
The pressure 1 is 4.882 atm.
Temperature 1 is to find?
The pressure on the next day is 4.690 atm.
The temperature on the next day is 8 °C
8 + 273.15 = 281 K
Putting the values in the equation
[tex]\rm \dfrac{4.882}{T_1} =\dfrac{4.690}{281}\\\\T_1 = 293 \;K[/tex]
293 K converting into Celsius
293 - 273.15 = 19.85 °C
Thus, the temperature on the previous day is 19.85 °C.
Learn more about temperature
https://brainly.com/question/11464844
#SPJ2
