Answer:
557.7Nm
Explanation:
We are given that
[tex]m=300 kg[/tex]
Radius,r=1.9 m
Angular speed,[tex]\omega=3.6rad/s[/tex]
Time,t=3.5 s
Initial angular velocity,[tex]\omega_0=0[/tex]
We have to find the large torque would have to be exerted .
[tex]\alpha=\frac{\omega-\omega_0}{t}=\frac{3.6-0}{3.5}=1.03rad/s^2[/tex]
[tex]\tau=I\alpha[/tex]
[tex]\tau=\frac{1}{2}mr^2\alpha[/tex]
Where [tex]I=\frac{1}{2}mr^2[/tex]
Substitute the values
[tex]\tau=\frac{1}{2}(300)(1.9)^2(1.03)=557.7Nm[/tex]
