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A current exists whenever electric charges move. If ΔQ is the net charge that passes through a surface during a time period Δt, then the average current during this time interval is defined as average current = ΔQ Δt = Q2 − Q1 t2 − t1 . If we take the limit of this average current over smaller and smaller time intervals, we get what is called the current I at a given time t1: I = lim Δt→0 ΔQ Δt = dQ dt . Thus the current is the rate at which charge flows through a surface. The current in a wire is defined as the derivative of the charge: I(t) = Q'(t). What does b I(t) a dt represent?

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asifejaz20

Answer:

It represents the change in charge Q from time t = a to t = b

Explanation:

As given in the question the current is defined as the derivative of charge.

                                  I(t) = dQ(t)/dt ..... (i)

But if we take the inegral of the equation (i) for the time interval  from t=a to

t =b we get

                                   Q =∫_a^b▒〖I(t)  〗 dt

which shows the change in charge Q from time t = a to t = b. Form here we can say that, change in charge is defiend as the integral of current for specific interval of time.

What the integral function [tex]\int\limits^b_a {I(t)} \, dt[/tex] represents is; change in the charge Q from time t = a to t = b.

We are given that current at a given time t₁ is represented by;

I(t) = Q'(t)

This means that current at a time t is the derivative of the charge Q with respect to time t.

Now, we want to know what [tex]\int\limits^b_a {I(t)} \, dt[/tex] represents.

Recall that I(t) is a derivative of the charge Q. This means that integrating I(t) tells us that we are trying to find the charge Q.

Finally, since integrating I(t) tells us that we are trying to find the charge Q, it means that at a boundary of b, a, we are trying to find the charge Q from time t = a to t = b.

Read more about electrical charges at; https://brainly.com/question/11956731

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