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At equilibrium, the concentrations of gaseous N2, O2, and NO in a sealed reaction vessel are [N2] 5 3.3 3 1023 M, [O2] 5 5.8 3 1023 M, and [NO] 5 3.1 3 1023 M. What is the value of Kc for the following reaction at the temperature of the mixture
N2(g)+O2(g) <---> 2 NO(g)

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sebassandin

Answer:

[tex]Kc=0.948[/tex]

Explanation:

Hello,

In this case, for the given chemical reaction, which is:

[tex]N_2(g)+O_2(g) \rightleftharpoons 2 NO(g)[/tex]

The law of mass action is:

[tex]Kc=\frac{[NO]^2}{[N_2][O_2]}[/tex]

Thus, for the given concentrations we obtain:

[tex]Kc=\frac{(5 3.1 3 1023 M)^2}{(5 3.3 3 1023 M)(5 5.8 3 1023 M)}\\Kc=0.948[/tex]

Best regards.

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