Respuesta :
Answer:
6.63g of MgO
Explanation:
Magnesium (Mg) reacts with oxygen (O) in
Equation of reaction
Mg + O₂ → MgO
From the stoichiometry of the reaction, 1 mole of Mg gives 1 mole of MgO
1 mole = molar mass
Molar mass of Mg = 24.3 g/mol
Molarmass of MgO = (24.3 + 16.0) = 40.3g/mol
24.3 g of Mg = 40.3g of MgO
4 g of Mg = x g of MgO
x = (4 * 40.3) / 24.3
x = 6.63 g of MgO
Answer:
We can produce 6.63 grams of Magnesium oxide
Explanation:
Step 1: Data given
Mass of magnesium = 4.00 grams
Molar mass of Magnesium = 24.305 g/mol
O2 is in excess
Molar mass of Magnesium oxide = 40.3044 g/mol
Step 2: The balanced equation
2Mg + O2 → 2MgO
For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide
Step 3: Calculate moles magnesium
Moles Mg = 4.00 grams / 24.305 g/mol
Moles Mg = 0.1646 moles
Step 4: Calculate moles Magnesiumoxide
For 2 moles Magnesium we need 1 mol oxygen gas to produce 2 moles magnesiumoxide
For 0.1646 moles Mg we'll have 0.1646 moles MgO
Step 5: Calculate mass magnesium oxide
Mass MgO = Moles MgO * molar mass MgO
Mass MgO = 0.1646 moles* 40.3044 g/mol
Mass MgO = 6.63 grams
We can produce 6.63 grams of Magnesium oxide