help plz. i would greatly appreciate it
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Answer:
1) [tex]5^2=25[/tex]
2) [tex]5^2=x[/tex]
3) [tex]b^3=64[/tex]
Step-by-step explanation:
To write logs of the form [tex]log_ba=x[/tex] in their exponential form, you take the base b and put it to the power of x and then set that equal to a: [tex]b^x=a[/tex].
1. Here, b = 5, a = 25, and x = 2, so: [tex]5^2=25[/tex]
2. In this problem, b = 5, x = 2, and a = x, so: [tex]5^2=x[/tex]
3. Finally, here, b = b, a = 64, and x = 3, so: [tex]b^3=64[/tex]
Hope this helps!
Answer:
1) 25 = 5²
2) x = 5²
3) 64 = b³
Step-by-step explanation:
logb(a) = x
a = b^x
log5(25) = 2
25 = 5²
log5(x) = 2
x = 5²
logb(64) = 3
64 = b³