Respuesta :
Answer:
The molarity of the HCl is 0.8924 M.
Explanation:
Use dimensional analysis to solve the problem.
28.6 mL x ([tex]\frac{1 L}{1000 mL}[/tex]) x ([tex]\frac{0.145 mole NaOH}{1 L}[/tex]) x ([tex]\frac{1 mole HCl}{1 mole NaOH}[/tex]) = 0.004147 moles HCl
Then we use M= moles/ liter to find the molarity.
M = 0.004147 moles HCl / 0.005 L
M = 0.8294
0.829 mol/L is the molarity of a solution of HCl if 5.00 mL of the HCl solution is titrated with 28.6 mL of a 0.145 M NaOH solution.
What is Molarity ?
Molarity (M) is defined as the number of moles of solute dissolved in 1 L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity (M) = [tex]\frac{\text{Number of moles }}{\text{Volume of solution in liters}}[/tex]
What is Stoichiometry ?
Stoichiometry helps us use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.
According to Stoichiometry
[tex]28.6\ mL \times \frac{1\ L}{1000\ mL} \times \frac{0.145\ \text{mole NaOH}}{1\ L} \times \frac{1\ \text{mole HCl}}{1\ \text{mole NaOH}}[/tex]
= 0.004147 moles of HCl
Change ml into L
1 mL = 0.001 L
5.00 mL = 5.00 × 0.001
= 0.005 L
Now put the value in above formula we get
Molarity (M) = [tex]\frac{\text{Number of moles }}{\text{Volume of solution in liters}}[/tex]
= [tex]\frac{0.004147\ mol}{0.005\ L}[/tex]
= 0.829 mol/L
Thus from above conclusion we can say that 0.829 mol/L is the molarity of a solution of HCl if 5.00 mL of the HCl solution is titrated with 28.6 mL of a 0.145 M NaOH solution.
Learn more about the Stoichiometry here: brainly.com/question/14935523
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