Answer:
43.96 L
Explanation:
We are given that
[tex]V_1=26.8 L[/tex]
[tex]P_1=744mm Hg[/tex]
[tex]T_1=31.2^{\circ} C=31.2+273=304.2K[/tex]
[tex]P_2=385mmHg[/tex]
[tex]T_2=-14.8^{\circ}=273-14.8=258.2K[/tex]
We know that
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
[tex]V_2=\frac{P_1V_1T_2}{P_2T_1}[/tex]
Substitute the values
[tex]V_2=\frac{744\times 26.8\times 258.2}{385\times 304.2}[/tex]
[tex]V_2=43.96 L[/tex]
Hence, the volume of balloon at -14.8 degree Celsius=43.96 L