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A group of 12 friends went bowling. They each rented shoes for $3.00 a pair, and 4 friends bowled 2 games each, while 8 friends bowled 3 games each. Each game bowled cost each person the same amount. The total cost for the shoe rentals and the games bowled was $212.00. What was the cost, in dollars, of each game bowled?

Respuesta :

calculista

Answer:

The cost of each game bowled was $5.50

Step-by-step explanation:

Let

x ---> the cost of rent a pair of shoes

y ---> the cost o each game bowled

we know that

The cost of rent each pair of shoes multiplied by the number of shoes plus the cost of each game bowled multiplied by the number of games bowled must be equal to $212.00

so

The linear equation that represent this situation is

[tex]12x+(4)(2)y+(8)(3)y=212[/tex]

[tex]12x+32y=212[/tex]

we have

[tex]x=\$3.00[/tex] ----> is given

substitute the value of x and solve for y

[tex]12(3)+32y=212\\32y=212-36\\32y=176\\y=\$5.50[/tex]

therefore

The cost of each game bowled was $5.50

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