A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?
Useful formulas include StartBracket upper H subscript 3 upper O superscript plus EndBracket equals 10 superscript negative p H., StartBracket upper O upper H superscript minus EndBracket equals 10 superscript negative p O H., p H plus P O H equals 14., and StartBracket upper H subscript 3 upper O superscript plus EndBracket StartBracket upper O upper H superscript minus EndBracket equals 10 to the negative 14 power..
1.58 x 10^–12 M
6.31 x 10^–3 M
2.20 M
158 M

Respuesta :

Answer:

The answer is 2.20 M

Explanation:

This is because ammonia has a pH of 11.8 and if you take 14-11.8 it equals 2.2 so the answer is 2.20 M

pH is the measure of the hydrogen ion concentration in an aqueous solution. The concentration of the hydroxide ions is 0.00631.

What is pOH?

pOH is the measure o the hydroxide ion concentration that depicts the basicity of the solution.

We know,

[tex]\rm pH + pOH = 14[/tex]

Given,

pH of the ammonia solution = 11.8

Substituting values in the equation pOH can be calculated as:

[tex]\begin{aligned} \rm pH + pOH &= 14\\\\&= 14 - 11.8\\\\&= 2.2\end{aligned}[/tex]

Thus, the pOH of the solution is 2.2.

Now the concentration of the hydroxide in the solution is calculated as:

[tex]\begin{aligned} \rm pOH &= - \rm log [OH^{-}]\\\\2.2 &= \rm - log [OH^{-}]\\\\&= 0.006309 \end{aligned}[/tex]

Therefore, option B. [tex]6.31 \times 10^{-3}\;\rm M[/tex] is the hydroxide concentration in the solution.

Learn more about pOH here:

https://brainly.com/question/15130754