Answer:
The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
Explanation:
Given:
(A)
Current [tex]I = 1[/tex] A
Voltage [tex]V = 12[/tex] V
For finding the resistance,
[tex]V = IR[/tex]
[tex]R = \frac{V}{I}[/tex]
[tex]R = \frac{12}{1}[/tex]
[tex]R =[/tex] 12Ω
(B)
For finding power delivered,
[tex]P = I^{2} R[/tex]
[tex]P = (1) ^{2} \times 12[/tex]
[tex]P = 12[/tex] Watt
(C)
For finding the potential difference,
[tex]V = IR[/tex]
[tex]V = 5 \times 10^{-3} \times 2[/tex]
[tex]V = 10 \times 10^{-3}[/tex]
[tex]V = 0.01[/tex] V
Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
