I plugged this into photo math, but apparently I have to pay to find out how to get the answer. can you guys help me out?
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Photo math is charging? We don't need it. We factor the difference of two squares.
[tex]\dfrac{5t^2-500}{t+10} = \dfrac{5(t^2- 100)}{t+10} = \dfrac{5(t-10)(t+10)}{t+10} = 5(t-10) = 5t-50[/tex]
Answer: 5t-50