Respuesta :
Answer:
a. Da = ¼ Db
Explanation:
Let us write out equations of motion for both objects:
For object A:
[tex]D_a = ut + \frac{1}{2}gt^2[/tex]
Since initial velocity, u =, is zero:
[tex]D_a = \frac{1}{2}gt^2[/tex] ---------------------------------------- (1)
For object B:
[tex]D_b = ut + \frac{1}{2}g(2t)^2\\\\\\D_b = ut + 2gt^2[/tex]
Since initial velocity, u =, is zero:
[tex]D_b = 2gt^2[/tex] ---------------------------------------- (2)
Note: g = acceleration due to gravity
To get the relationship between Da and Db, we make g subject of formula in (1) and (2) and then equate:
From (1):
[tex]g = \frac{2D_a}{t^2}[/tex]
From (2):
[tex]g = \frac{D_b}{2t^2}[/tex]
Equating:
=> [tex]\frac{2D_a}{t^2} = \frac{D_b}{2t^2} \\\\\\D_a = \frac{D_b}{4} \\\\\\D_a = \frac{1}{4} D_b[/tex]
