Answer:
The true weight of the aluminium is [tex]m_{alu} =[/tex] 4.5021 kg
Explanation:
Given data
[tex]m_{app}[/tex] = 4.5 kg
[tex]\rho_{air}[/tex] = 1.29 [tex]\frac{kg}{m^{3} }[/tex]
[tex]\rho_{al}[/tex] = 2.7× [tex]10^{3} \frac{kg}{m^{3} }[/tex]
The true mass of the aluminium is given by
[tex]m_{alu} = \frac{\rho_{alu}m_{app}}{\rho_{alu} -\rho_{air} }[/tex]
Put all the values in above equation we get
[tex]m_{alu} = \frac{(2700)(4.5)}{2700-1.29}[/tex]
[tex]m_{alu} =[/tex] 4.5021 kg
Therefore the true weight of the aluminium is [tex]m_{alu} =[/tex] 4.5021 kg
