Respuesta :
Answer:
∆temperature = 175781.25°
Explanation:
Kinetic energy = 1/2 * mv²
Kinectic energy= 1/2 * 5 * 300²
Kinectic energy = 2.5 * 90000
Kinectic energy= 225000 joules.
If half is transmitted to tree..
If 225000/2 = 112500 joules
Mc∆temperature = energy
Mc∆temperature = 112500
∆temperature = 112500/mc
∆temperature= (112500)/((5/1000)*128)
∆temperature= 112500/0.64
∆temperature = 175781.25°
the conservation of energy allows to find the result for the change in temperature of the bullet is:
ΔT = 195ºC
Given parameters
- Mass of the bullet m = 5 g = 5 10-3 kg
- Bullet velocity v = 300 m / s
- Half of the energy is transformed into internal energy in the bullet.
- Specific heat lead ce = 128 J / kg ºC
To find
- Bullet temperature change.
The conservation of energy is an important law of conservation of physics, stable that energy cannot be created, not destroyed only transformed.
Let's look for the mechanical energy of the bullet that is totally kinetic.
Em = K = ½ m v²
Em = ½ 5 10-3 (300) ²
Em = 2.25 10² J
They indicate that half is transformed into internal energy.
U = Em / 2
U = 2.25 10² / 2
U = 1.25 10² J
The energy is
U = Q = [tex]m c_e \Delta T[/tex]
ΔT= [tex]\frac{Q}{m \ c_e}[/tex]
Let's calculate.
ΔT = [tex]\frac{1.25 \ 10^{2}}{5 \ 10^{-3} \ 128}[/tex]
ΔT = 1.95 10²
ΔT = 195ºc
In conclusion using the conservation of energy we can find the result for the change in temperature of the bullet is:
ΔT = 195ºC
Learn more here: brainly.com/question/13010190
