Answer:
0.0656 is the probability that exactly five of the trainees will still be employed at the end of nine months.
Step-by-step explanation:
We are given the following information:
We treat management trainees still employed at the end of nine months as a success.
P(Employed) = 29% = 0.29
Then the number of trainees follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 9
P(exactly five of the trainees will still be employed at the end of nine months)
We have to evaluate:
[tex]P(x =5)\\\\= \binom{9}{5}(0.29)^5(1-0.29)^4\\\\= 0.0656[/tex]
0.0656 is the probability that exactly five of the trainees will still be employed at the end of nine months.
