Answer:
he sampling distribution of p is normal with mean p = 0.12
the standard deviation = [tex]\sqrt{\frac{p(1-p)}{n} } =\sqrt{\frac{0.12(1-0.12)}{540} }=0.014[/tex]
Step-by-step explanation:
A sampling distribution is a probability distribution obtained from a larger number of samples gotten from a specific population. It shows all the possible result that can be gotten from each sample of a population
Given that:
p = 12% = 0.12
n = 540
the sampling distribution of p is normal with mean p = 0.12
the standard deviation = [tex]\sqrt{\frac{p(1-p)}{n} } =\sqrt{\frac{0.12(1-0.12)}{540} }=0.014[/tex]
It is shown in the graph attached
