Answer:
500 CDs and 300 DVDs.
Step-by-step explanation:
Given:
The owner of a music store ordered merchandise with a total value of $11000 from her supplier.
She ordered CDs costing $10 each and DVDs costing $20 each.
If she ordered 200 more CDs than DVDs.
Question asked:
How many of each did she order?
Solution:
Let number of DVDs ordered by her = [tex]x[/tex]
Then the number of CDs ordered by her = [tex]x+200[/tex]
Cost of 1 CD = $10
Cost of [tex]x+200[/tex] CDs = [tex]10(x+200)=10x+2000[/tex]
Cost of 1 DVD = $20
Cost of [tex]x[/tex] DVD = [tex]20x[/tex]
Total value of her ordered = $11000
Cost of [tex]x+200[/tex] CDs + Cost of [tex]x[/tex] DVDs = $11000
[tex]10x+2000+20x=11000\\ \\ 30x+2000=11000\\ \\ Subtracting\ both\ sides\ by\ 2000\\ \\ 30x+2000-2000=11000-2000\\ \\ 30x=9000\\ \\ Dividing\ both\ sides\ by \ 30 \\ \\ x=300[/tex]
Number of DVDs ordered by her = [tex]x[/tex] = 300
Number of CDs ordered by her = [tex]x+200[/tex] = 300 + 200 = 500
Therefore, she ordered 500 CDs and 300 DVDs from her supplier.
