Respuesta :
Answer: C) 0.1151.
Step-by-step explanation:
Hi, to answer this question we have to apply the formula
P =2w +2 L
Where:
P=perimeter
W= width
Hi, to answer this question we have to calculate the z score:
z= ( X-μ /σ)
Where:
X: variable
μ : mean
σ:standard deviation
Replacing with the values given and solving:
P ( X <250) = P ( X-μ /σ < [250-268]/ 15)
P= z <-1.2
the probability(P) associated with a z-score of -1.2 is C) 0.1151. (looking in the table of z-scores)
The probability of a pregnancy lasting less than 250 days is 0.1151 and this can be determined by using the z-score formula.
Given :
The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a standard deviation of 15 days.
First, determine the z-score in order to determine the probability of a pregnancy lasting less than 250 days.
The formula of the z-score is given below:
[tex]\rm z = \dfrac{x-\mu}{\sigma}[/tex]
Now, substitute the values of the known terms in the above formula.
[tex]\rm z = \dfrac{250-268}{15}[/tex]
z = -1.2
Now, the probability of a pregnancy lasting less than 250 days is:
P(X < 250) = P(z < -1.2)
P(X < 250) = 0.1151
Therefore, the correct option is C).
For more information, refer to the link given below:
https://brainly.com/question/13299273
