Answer:
There is at least one instant which instantaneous acceleration is equal to average acceleration. [tex]a = 1500\,\frac{km}{h^{2}}[/tex].
Explanation:
The average acceleration experimented by the car is:
[tex]\bar a = \frac{85\,\frac{km}{h} - 35\,\frac{km}{h} }{\frac{2}{60}\,h }[/tex]
[tex]\bar a = 1500\,\frac{km}{h^{2}}[/tex]
According to the Rolle's Theorem, there is at least one instant t so that instantaneous acceleration equal to average acceleration for the analyzed interval. That is to say:
[tex]v'(c) = \frac{v(\frac{2}{60} )-v(0)}{\frac{2}{60}-0}[/tex]
If car is accelerating at constant rate, instantaneous acceleration coincides with average acceleration for all instant t. Then, instantaneous acceleration is:
[tex]a = 1500\,\frac{km}{h^{2}}[/tex]
