Answer: Thus the volume of the balloon at that new location is [tex]4.65\times 10^4L[/tex]
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 0.995 atm
[tex]P_2[/tex] = final pressure of gas = 0.720 atm
[tex]V_1[/tex] = initial volume of gas = [tex]3.93\times 10^4L[/tex]
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]32.0^oC=273+32.0=305.0K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-11.7^oC=273-11.7=261.3K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{0.995\times 3.93\times 10^4}{305.0}=\frac{0.720\times V_2}{261.3}[/tex]
[tex]V_2=4.65\times 10^4L[/tex]
Thus the volume of the balloon at that new location is [tex]4.65\times 10^4L[/tex]
