Answer:
0.868M Cu⁺
Explanation:
The reaction is:
KMnO₄ + 5Cu⁺ + 8H⁺ → 5Cu²⁺ + Mn²⁺ + K⁺ + 4H₂O
Where 1 mol of KMnO₄ reacts with 5 moles of Cu⁺
3.30x10⁻²L of 0.132M KMnO₄ are:
3.30x10⁻²L × (0.132mol KMnO₄ / L) = 4.356x10⁻³mol KMnO₄
As 1 mol reacts with 5 moles of Cu⁺, moles of Cu⁺ are:
4.356x10⁻³mol KMnO₄ × (5mol Cu⁺ / 1mol KMnO₄) = 0.02178moles Cu⁺
As these moles are in 2.51x10⁻²L, the starting concentration of the Cu⁺ solution is:
0.02178moles Cu⁺ / 2.51x10⁻²L = 0.868M Cu⁺
