Answer:
wavelength [tex]\lambda[/tex] = 5.50 m
The period T = 5.80 s
The speed v = 0.948 m/s
Amplitude A of each wave = 0.350 m
Explanation:
Since the wave crests is 5.50 m; then we can say that the distance from one peak to another is equal to a single wavelength;
SO; wavelength [tex]\lambda[/tex] = 5.50 m
Given that ; the time to travel from the highest point to the lowest point = 2.90 s
Thus [tex]t_{1/2} = 2.90 \ s[/tex] ; which implies just only about half of one wavelength
The period for one wavelength T = twice of half of one wavelength which can be expressed as :
T = [tex]2 t_{1/2}[/tex]
T = 2 (2.90 s)
T = 5.80 s
The speed of the wave can be determined via the formula;
[tex]v = \frac{\lambda}{T}\\\\v = \frac{5.50 \ m}{5.80 \ s}\\\\v = 0.948 \ m/s[/tex]
The amplitude A is half the distance because the distance illustrates the peak to peak vertical displacement of the wave ;
∴
A = [tex]\frac{0.700 \ m}{2}[/tex]
A = 0.350 m
