Answer:
2n[tex]\sqrt{n}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]
Given
[tex]\frac{1}{3}[/tex][tex]\sqrt{18n^2}[/tex] × [tex]\sqrt{2n}[/tex]
= [tex]\frac{1}{3}[/tex] × [tex]\sqrt{18}[/tex] × [tex]\sqrt{n^2}[/tex] × [tex]\sqrt{2}[/tex] × [tex]\sqrt{n}[/tex]
= [tex]\frac{1}{3}[/tex] × [tex]\sqrt{36}[/tex] × n × [tex]\sqrt{n}[/tex]
= [tex]\frac{1}{3}[/tex] × 6 × n × [tex]\sqrt{n}[/tex]
= 2n[tex]\sqrt{n}[/tex]
