Determine the value of x.
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Answer:
x = 6[tex]\sqrt{2}[/tex]
Step-by-step explanation:
Note the triangle is a right- isosceles, with equal legs = 6
Using Pythagoras' identity on the right triangle.
x² = 6² + 6² = 36 + 36 = 72 ( take the square root of both sides )
x = [tex]\sqrt{72}[/tex] = [tex]\sqrt{36(2)}[/tex] = [tex]\sqrt{36}[/tex] × [tex]\sqrt{2}[/tex] = 6[tex]\sqrt{2}[/tex]
Answer:
6[tex]\sqrt{2}[/tex]
Step-by-step explanation:
We should be using pythagoras theorem
6^2 + 6^2 = 72
[tex]\sqrt{72}[/tex] is the length of x
it is also equal to [tex]\sqrt{36*2}[/tex]
The square root of 36 is 6
and the square root of 2 is [tex]\sqrt{2}[/tex]
Thus the ans is 6[tex]\sqrt{2}[/tex]