jenymachado31737 jenymachado31737

14-04-2020
Mathematics

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For a binomial distribution the Mean is equal to np and the Variance is npq.
If n = 346 and p = 0.2 , what is the Standard Deviation?

Respuesta :

emma23131 emma23131

14-04-2020

Answer:

7.44

Step-by-step explanation:

formula for SD is [tex]\sqrt{npq}[/tex] since we dont have q, we find q by (1-p)

so now its [tex]\sqrt{np(1-p)}[/tex] or [tex]\sqrt{346*0.2*(1-0.2)}[/tex]

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