Answer:
[tex]\huge\boxed{\tan x=\dfrac{\sin x}{\cos x}}[/tex]
Step-by-step explanation:
[tex]\tan x\cos x=\sin x\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\text{Therefore}\\\\\tan x\cos x=\dfrac{\sin x}{\cos x}\cdot\cos x\qquad\text{cancel}\ \cos x\\\\\tan x\cos x=\sin x\\\\\text{For}\ x\neq\dfrac{\pi}{2}+k\pi},\ k\in\mathbb{Z}[/tex]
