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If I have 2 liters of gas held at a pressure of 78 atm and a temperature of 900 k, what will be the volume of the gas if I decrease the pressure to 45 atm and decrease the temperature to 750k

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emaikwuvictor

Answer:

V2 = 2.88L

Explanation:

P1= 78atm, V1= 2L, T1= 900K, P2= 45atm, V2=? T2= 750K

Applying the general gas equation

P1V1/T1 = P2V2/T2

Substitute the above

(78*2)/900= (45*V2)/750

V2= (78*2×750)/(900*45)

V2= 2.88L

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