Respuesta :
The answer for the given problem is mentioned below.
1. Therefore 7.5 moles of oxygen is required to react with 10 moles of Al.
2.Therefore 12 moles of Al is required to react with 6 moles of aluminium oxide.
Explanation:
Given:
An equation;
4 Al + 3 [tex]O_{2}[/tex] → 2 [tex]Al_{2}O_{3}[/tex]
To find :
1. no of moles of oxygen([tex]O_{2}[/tex] )
2. no of moles of aluminium (Al)
We know;
1.
4 Al + 3 [tex]O_{2}[/tex] → 2 [tex]Al_{2}O_{3}[/tex]
Here;
Al represents Aluminium
[tex]O_{2}[/tex] represents oxygen
[tex]Al_{2}O_{3}[/tex] represents aluminium oxide
4 moles of Al → 3 moles of [tex]O_{2}[/tex]
10 moles of Al → ?
Therefore;
n = [tex]\frac{10 * 3}{4}[/tex]
n = 7.5 moles of oxygen
Therefore 7.5 moles of oxygen is required to react with 10 moles of Al.
2.
4 Al + 3 [tex]O_{2}[/tex] → 2 [tex]Al_{2}O_{3}[/tex]
Here;
Al represents Aluminium
[tex]O_{2}[/tex] represents oxygen
[tex]Al_{2}O_{3}[/tex] represents aluminium oxide
4 moles of Al → 2 moles of [tex]Al_{2}O_{3}[/tex]
→ 6 moles of [tex]Al_{2}O_{3}[/tex]
Therefore;
n = [tex]\frac{6 * 4}{2}[/tex]
n = 12 moles of Al
Therefore 12 moles of Al is required to react with 6 moles of aluminium oxide.
The number of O₂ that would need to react with 10 moles of Al is 7.5 moles
The number of moles of Al that would need to make 6 moles of Al₂O₃ is 12 moles.
Balanced equation
4Al + 3O₂ → 2Al₂O₃
4 moles of aluminium = 3 moles of oxygen
10 moles of aluminium = ?
cross multiply
moles of oxygen = 10 × 3 / 4 = 30 / 4 = 7.5 moles
2 moles of Aluminium oxide requires 4 moles of Aluminium
6 moles of Aluminium oxide will require ? of aluminium
cross multiply
moles of Aluminium = 6 × 4 / 2 = 24 / 2 = 12 moles
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