The pH for a 0.142M solution of NaHA is 1.0
Explanation:
Calculating the PH value based on the given data H2A
H2A with Ka1 = 2.3× 10–4
The concentration of the acid is 0.180 M and the Ka1 is 2.3×10–4
Rewrite the chemical equation as,
H2A --> H+1 + HA−1 with Ka1 = 2.3× 10–4
Bythe formula:
Ka=(products) / (reactants):
2.3× 10–4 = (x2)/(0.180)
x2= 0.180 × 2.3× 10–4
x= 0.414 ×10^-4 =[H+]
x= 4.14 ×10^-3 =[H+]
Since pH = -log of hydrogen ion concentration,
The pH for a 0.142M solution of NaHA is 1.0
