The answer for the following problem is mentioned below.
- Therefore the final volume of the gas is 52.7 ml.
Explanation:
Given:
Initial pressure ([tex]P_{1}[/tex]) = 290 kPa
Final pressure ([tex]P_{2}[/tex]) = 104 kPa
Initial volume ([tex]V_{1}[/tex]) = 18.9 ml
To find:
Final volume ([tex]V_{2}[/tex])
We know;
From the ideal gas equation;
P × V = n × R × T
where;
P represents the pressure of the gas
V represents the volume of gas
n represents the no of the moles
R represents the universal gas constant
T represents the temperature of the gas
So;
P × V = constant
P ∝ [tex]\frac{1}{V}[/tex]
From the above equation;
[tex]\frac{P_{1} }{P_{2} } = \frac{V_{2} }{V_{1} }[/tex]
[tex]P_{1}[/tex] represents the initial pressure of the gas
[tex]P_{2}[/tex] represents the final pressure of the gas
[tex]V_{1}[/tex] represents the initial volume of the gas
[tex]V_{2}[/tex] represents the final volume of the gas
Substituting the values of the above equation;
[tex]\frac{290}{104}[/tex] = [tex]\frac{V_{2} }{18.9}[/tex]
[tex]V_{2}[/tex] = 52.7 ml
Therefore the final volume of the gas is 52.7 ml.
