Respuesta :
If 684.6g of sucrose (table sugar) are dissolved in 4 liters of water, the molarity of the solution is 0.47 M
Explanation:
Data given:
mass of sugar = 684.6 grams
molar mass of sucrose = 342.3 grams/mole
volume of water = 4 litres
molarity = ?
molarity is given by the formula = [tex]\frac{number of moles}{volume in litres}[/tex] equation 1
number of moles = [tex]\frac{mass}{atomic mass}[/tex] equation 2
For number of moles of sucrose equation 2 is used
putting values in it
number of moles =[tex]\frac{648.6}{342.3}[/tex]
1.89 moles of sucrose are given.
to known the molarity values are put in first equation or formula:
molarity = [tex]\frac{1.89}{4}[/tex]
molarity = 0.47 M
thus the molarity of 648.6 grams of sugar in 4 litres of solution is 0.47 M
Molarity of the sucrose solution is 0.5 M.
Explanation:
The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,
Number of moles = [tex]$\frac{given mass}{molar mass}[/tex]
= [tex]$\frac{684.6 g }{342.3 g/mol}[/tex]
= 2 moles
Molarity = [tex]$\frac{moles}{Volume (L)}[/tex]
= [tex]$\frac{2}{4} \\[/tex]
= 0.5 moles / litre (mol/ L) or 0.5 M
So the molarity of the sucrose solution is 0.5 M.
