Respuesta :
The answer for the following problem has been mentioned below.
- Therefore the mass of the water is 5.802 grams.
Explanation:
Given:
volume of oxygen (V) = 4.50 L
Temperature (T) = 425 K
pressure of oxygen (P) = 2.50 atm
Gram molecular mass of oxygen (M) = 16.0 grams
To calculate:
mass of water (m)
We know;
According to the ideal gas equation;
P × V = n × R × T
As we know;
no of moles = [tex]\frac{m}{M}[/tex]
m represents the mass of oxygen (m)
M represents the Gram molecular mass (M)
According to above mentioned equation;
P × V = n × R × T
P represents the pressure of the oxygen
V represents the volume of the oxygen
n represents the no of moles of the oxygen
R represents the universal gas constant
where,
the value of R is 0.0821 L atm/K moles
Substituting the values in the above equation;
2.50 × 4.50 = [tex]\frac{m}{16.0}[/tex] × 0.0821 × 425
11.25 = [tex]\frac{m}{16.0}[/tex] × 34.8925
180 = m × 34.8925
m = [tex]\frac{180}{34.8925}[/tex]
m = 5.158 grams
Therefore the mass of the of oxygen is 5.158 grams
Now;
As we know;
[tex]\frac{m_{1} }{M_{1} } = \frac{m_{2} }{M_{2} }[/tex]
where;
[tex]m_{1}[/tex] represents the mass of the oxygen
[tex]M_{1}[/tex] represents the gram molecular mass of the oxygen
[tex]m_{2}[/tex] represents the mass of the water
[tex]M_{2}[/tex] represents the gram molecular mass of water
From the above given formula,
[tex]\frac{5.158}{16.0}[/tex] = [tex]\frac{m_{2} }{18}[/tex]
where;
Gram molecular weight of water = 18.0 u
[tex]m_{2}[/tex] = 5.802 grams
Therefore the mass of the water is 5.802 grams.
