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How many real solutions does this system of equations have? X^2+ 3 = y
3x-y+1 = 0
Answer choices:
A.2
B.1
C.0
D.3

Respuesta :

Answer:

A

Step-by-step explanation:

x^2+3=y

3x-y+1=0

3x+1=y

so x²+3=3x+1

x²-3x+2=0

x²-x-2x+2=0

x(x-1)-2(x-1)=0

(x-1)(x-2)=0

x=1,2

two solutions

zaralovey221

Answer:

took the L for my gang

Step-by-step explanation:

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