Answer:
18M
Explanation:
Given parameters:
Initial volume of acetic acid = 100mL
Final volume of solution = 1200mL = 1.2L
Final molarity = 1.5M
Unknown:
Initial molarity = ?
Solution:
We might desired a particular concentration of a compound from the stock. This way, we dilute using the right amount of solvent. One critical thing to note is that the number of moles in both solution remains the same.
To solve this problem, let us find the number of moles in the final solution.
Number of moles in final solution = molarity x volume
= 1.5 x 1.2
= 1.8mol
Now original molarity;
Since Molarity = [tex]\frac{number of moles}{volume}[/tex]
Molarity = [tex]\frac{1.8}{0.1}[/tex] = 18M
