Respuesta :
The specific heat capacity of Titanium is found as 0.522 J / g°C.
Explanation:
We have to find the specific capacity using the formula as,
q = m × c × ΔT
Where,
q is the heat absorbed by the sample = 476 J
m is the mass of the sample = 43.56 g
c is the specific heat capacity of the sample = ?
ΔT is the temperature difference = 41.06° C - 20.13°C = 20.93° C
Now, we have to rewrite the equation to get the specific heat capacity as,
c = [tex]$\frac{q}{m \times dT}[/tex]
= [tex]$\frac{476 }{43.56\times 20.93}[/tex]
= 0.522 J / g°C
So the specific heat capacity of Titanium is found as 0.522 J / g°C.
The specific heat capacity of titanium if a 43.56 g sample absorbs 476 J 0.522 J / g°C.
What is specific heat capacity?
When the temperature of a material rises 1 K (or 1 °C), the amount of heat (J) absorbed per unit mass (kg),
[tex]c = \dfrac{q }{m \times dt} \\\\\\c = \dfrac{476 }{43.56 \times 20.93} = 0.522[/tex]
Thus, the specific heat capacity of titanium if a 43.56 g sample absorbs 476 J 0.522 J / g°C.
Learn more about specific heat capacity
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