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15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl calculated in grams?

Respuesta :

Neetoo

Answer:

41.56 g

Explanation:

Given data:

Mass of NH₄Cl = 15.50 g

Actual yield of AgCl = 35.50 g

Theoretical yield of AgCl = ?

Solution:

Chemical equation:

NH₄Cl  + AgNO₃      →     AgCl   + NH₄NO₃

Number of moles of NH₄Cl:

Number of moles = mass/ molar mass

Number of moles = 15.50 g/ 53.491 g/mol

Number of moles = 0.29 mol

Now we will compare the moles of NH₄Cl with   AgCl .

                     NH₄Cl            :               AgCl

                        1                  :                 1

                     0.29              :                0.29

Theoretical yield of AgCl:

Mass = number of moles × molar mass

Mass = 0.29 mol ×143.32 g/mol

Mass = 41.56 g

The theoretical yield of AgCl calculated in grams is 41.56 g

Calculation of the theoretical yield:

Since 15.50 g of NH4Cl reacts with an excess of AgNO3. And, the reaction 35.50 g AgCl is produced

The Chemical equation is

NH₄Cl  + AgNO₃      →     AgCl   + NH₄NO₃

Now A number of moles of NH₄Cl is

= mass/ molar mass

=  15.50 g/ 53.491 g/mol

= 0.29 mol

Here comparison should be made between the moles of NH₄Cl with   AgCl .

                    NH₄Cl            :               AgCl

                       1                  :                 1

                    0.29              :                0.29

Now Theoretical yield of AgCl:

Mass = number of moles × molar mass

= 0.29 mol ×143.32 g/mol

= 41.56 g

learn more about reaction here: https://brainly.com/question/10052452?referrer=searchResults

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