What is the volume of the cone to the nearest tenth?
401.2 yd?
421.4 yd
484.3 yd?
536.2 yd
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Answer:
536.2 yd^2
Step-by-step explanation:
volume of the cone is equal to
1/3 π r^2h {here h is height of cone & r is radius}
i.e, 1/3 ×π × (8yd)^2 × 8yd
= 536.16 yd^2
≈536.2 yd^2
✌️:)