Answer:
n= (C/4) -9
Step-by-step explanation:
The equation that in this problem describes the total charge for a trophy order with n lines of engraving is:
[tex]C=36+4n[/tex]
where
n is the number of lines of engraving
We want to re-arrange the equation to solve for n in terms of C. To do that, we proceed as follows:
1) First, we subtract 36 from both sides of the equation. We get:
[tex]C-36 = 36-36+4n\\C-36=4n[/tex]
2) Now, we divide by 4 both sides of the equation. We get:
[tex]\frac{C-36}{4}=\frac{4n}{4}\\\rightarrow n=\frac{C-36}{4}[/tex]
3) Finally, we divide each of the terms on the right by 4. We get:
[tex]n=\frac{C}{4}-\frac{36}{4}\\\rightarrow C=\frac{C}{4}-9[/tex]
So the correct answer is
n= (C/4) -9
