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Which equations represent circles that have a diameter of 12 units and a center that lies on the y-axis? Select two options
x2 + (y - 3)2 = 36
x2 + (y – 5)2 = 6
(x – 4)2 + y2 = 36
(x + 6)2 + y2 = 144
x2 + (y + 8)2 = 36

Respuesta :

Xopibies753

Answer:

The answer is A and E

x2+(y−3)2=36

x^{2}+(y+8)^{2}=36x2+(y+8)2=36

abidemiokin

The required equation of the circle is [tex]x^2+(y-3)^2=36[/tex]

Equation of a circle

The formula for finding an equation of a circle is expressed as:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where;

(a, b) is the centre of the circle

r is the radius of the circle

Given the following

diameter = 12units

r = 6 units

If a center lies on the y-axis, then the center can be (0, 3)

Substitute into the formula to have:

[tex](x-0)^2+(y-3)^2=6^2\\x^2+(y-3)^2=36[/tex]

Hence the required equation of the circle is [tex]x^2+(y-3)^2=36[/tex]

Learn more on equation of a circle here: https://brainly.com/question/24810873

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