Step-by-step explanation:
x^4+4y=8xy
=>8xy-4y=x^4
=>4y(2x-1)=x^4
=>4y=x^4/(2x-1)
differentiating both side we got
4 dy/dx={4x^3(2x-1)-2x^4}/(2x-1)^2
i.e, dy/dx=(6x^4-4x^3)/4(2x-1)^2
=(6x^4-4x^3)/(16x^2-16x+4)
✌️:)
