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A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decreased to 0.593 L. What is the new pressure in kilopascals?

Respuesta :

Edufirst

Answer:

  • 355 kPa

Explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

       [tex]PV=constant[/tex]

       [tex]P_1V_1=P_2V_2[/tex]

       [tex]P_2=\dfrac{P_1V_1}{V_2}[/tex]

Subsituting and computing:

     [tex]P_2=\dfrac{1.643L\times 128kPa}{0.593L}\approx355kPa[/tex]

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