1.75 g of 200g sample will remain radioactive after 1 hour
Explanation:
Given:
Decay rate, r = 0.079 per minute
Time, t = 1 hr = 60 min
Amount of the sample = 200 g
According to decay formula:
[tex]y(t) = y_o e^-^r^t[/tex]
On substituting the value we get:
[tex]y(60) = 200 X e^-^0^.^0^7^9^X^6^0\\\\y(60) = 200 X e^-^4^.^7^4\\\\y(60) = 1.75[/tex]
Therefore, 1.75 g of 200g sample will remain radioactive after 1 hour
