Answer:
Area of the rhombus is [tex]50\sqrt{3}[/tex] = [tex]86.6[/tex] cm^2
Step-by-step explanation:
Given:
A rhombus TURN with angle T measures 60 degrees.
Side length of the rhombus = 10 cm
Note:
Whenever a side length ([tex]s[/tex]) and an angle ([tex]\theta[/tex]) of the rhombus were given.
Its area = (s)^2 sin([tex]\theta[/tex])
Area of the rhombus :
⇒ [tex]A=(s)^2\times sin(\theta)[/tex]
⇒ [tex]A=(10)^2\times sin(60)[/tex]
⇒ [tex]A=100\times sin(60)[/tex]
⇒ [tex]A=100\frac{\sqrt{3} }{2}[/tex]
⇒ [tex]A=50\sqrt{3}[/tex] cm^2
So,
The area of the rhombus is 50*sq-rt(3) cm^2
