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Consider the polynomial function p given by p(x)=7x^3-2x^2+3x+10. Evaluate the function for p(-3). Show your work.
-- In the function p(x) identify the leading coefficient, constant, and degree.

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sfkaleho

Answer:

[tex]p(-3)=-206[/tex]

Step-by-step explanation:

[tex]p(-3)=7x^3-2x^2+3x+10[/tex]

[tex]p(-3)=7(-3)^3-2(-3)^2+3(-3)+10[/tex]

[tex]p(-3)= 7(-27)-2(9)-9+10[/tex]

[tex]p(-3)= -189-18-9+10[/tex]

[tex]p(-3)= -206[/tex]

In the function p(x), the leading coefficient is 7, the constant is 10, and the degree is 3.

Hope this helps!

Using polynomial concepts, it is found that:

  • p(-3) = -206.
  • The leading coefficient is 7.
  • The constant is 10.
  • The polynomial is of the 3rd degree.

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The polynomial function given is:

[tex]p(x) = 7x^3 - 2x^2 + 3x + 10[/tex]

p(-3) is given when x = -3, thus:

[tex]p(-3) = 7(-3)^3 - 2(-3)^2 + 3(-3) + 10 = -206[/tex]

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  • The degree is the highest power of x, which is 3, so 3rd degree.
  • Thea leading coefficient is the term that multiplies [tex]x^3[/tex], thus 7.
  • The constant is [tex]p(0) = 7(0)^3 - 2(0)^2 + 3(0) + 10 = 10[/tex]

A similar problem is given at https://brainly.com/question/21093330

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