Answer:
[tex]\huge\boxed{p(6)=45}[/tex]
Step-by-step explanation:
[tex]p(6)-\text{put}\ x=6\ \text{to the equation of the function}\ p(x)=x^2+x+3:\\\\p(6)=6^2+6+3\qquad\text{first - exponentiation}\\\\p(6)=36+6+3\qquad\text{last - addition}\\\\P(6)=45[/tex]
