Respuesta :
Answer:
2x + 7
Step-by-step explanation:
For x > -1,
x + 2 is positive
So, |x + 2| = x + 2
For x > -1,
x + 5 is positive
So, |x + 5| = x + 5
lx + 2l + lx + 5l = x + 2 + x + 5
= 2x + 7
Additional (in case range is also required)
lx + 2l
x > -1
lx + 2l > 1
lx + 5l
x > -1
lx + 5l > 4
lx + 2l + lx + 5l > 1 + 4
lx + 2l + lx + 5l > 5
Answer:
2x+7 when x>-1
Step-by-step explanation:
lx + 2l + lx + 5l
We know that x > -1
Let x be -1 the minimum value
lx + 2l = l-1 + 2l = l1l so it will always be greater than 0
We can remove the absolute value signs
Let x be -1 the minimum value
lx + 5l = l-1 + 5l = l4l so it will always be greater than 0
We can remove the absolute value signs
x + 2+ x + 5 when x>-1
2x+7